Body weight in water 2H. The buoyant force acting on it is 0.5 N. Find the mass of the body

Body weight in water 2H. The buoyant force acting on it is 0.5 N. Find the mass of the body, its volume and the density of the material from which the body is made.

PB = 2 N.

Farch = 0.5 N.

g = 9.8 m / s2.

ρw = 1000 kg / m3.

m -?

V -?

ρ -?

The weight of a body in the air P is determined by the formula: P = m * g, where m is the mass of the body, g is the acceleration of gravity.

m = P / g.

In water, the buoyancy force of Archimedes acts on the body, which is determined by the formula: Farch = ρw * g * V. Where ρw is the density of the liquid in which the body is immersed, g is the acceleration of gravity, V is the volume of the immersed part of the body in the liquid.

V = Farch / ρw * g.

V = 0.5 N / 1000 kg / m3 * 9.8 m / s2 = 0.00005 m3.

In water, the body weight Рв is determined by the formula: Рв = Р – Farch.

P = Pv + Farch.

m = (Pv + Farch) / g.

m = (2 N + 0.5 N) / 9.8 m / s2 = 0.255 kg.

ρ = m / V.

ρ = 0.255 kg / 0.00005 m3 = 5100 kg / m3.

Answer: V = 0.00005 m3, m = 0.255 kg, ρ = 5100 kg / m3.