Build a rectangle with sides 10 cm and 2 cm, find one third of its perimeter and seven tenths of its area.

1. Let’s calculate what the perimeter of a given rectangle is, if from the data presented in the problem statement we know that the lengths of its sides are 2 cm and 10 cm.

P = 2 + 2 + 10 + 10 = 24 cm.

2. Now let’s calculate what is 1/3 of the perimeter of this rectangle.

24 * 1/3 = 24/3 = 8 cm.

3. Now let’s calculate what is the area of this rectangle.

2 * 10 = 20 cm ^ 2.

4. Now let’s define what is equal to 7/10 of the area of the given rectangle.

20 * 7/10 = (20 * 7) / 10 = (2 * 7) / 1 = 14 cm.