Burned 100 grams of coal containing 10% impurities. Calculate the amount of carbon dioxide produced.

We were given 100 grams of coal with a 10% impurity content. This means that the mass of frequent coal is 100 * 0.9 = 90 grams. Chem. The designation for carbon is C. Let’s write the reaction of carbon combustion in oxygen:

C + 02 = C02

The number of moles of carbon is 90: 12 = 7.5

According to the reaction, mol C = mol CO2 = 7.5 mol

The volume is calculated by the formula V = n * 22.4, where n is moles, v is volume, 22.4 is how many liters are contained in 1 mole of any gas at normal

V = 7.5 * 22.4 = 168 liters

Answer: 168 liters



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