Burned 400 g of magnesium. Find the mass of magnesium oxide if the yield is 90%.

univerkov | December 20, 2020 | education

2Mg + O2 = 2MgO
n = m / M
n (Mg) = 400/24 = 16.67 mol = n (MgO)
m (MgO) = 16.67 * 40 = 666.67 g
m (MgO) pr = 666.67 * 0.9 = 600 g

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