Burned hexane. Calculate the mass of the burned hydrocarbon if 50 dm3 of gas is released as a result.

Let’s implement the solution:
1. According to the problem statement, we write the equation:
X g -? V = 50 dm3;
2C6H14 + 19O2 = 12CO2 + 14H2O – reaction of combustion of hexane, carbon monoxide (4) and water are released;
2. Calculations by formulas:
M (C6H14) = 86 g / mol;
M (CO2) = 44 g / mol;
1 dm3 = 1 l;
V (CO2) = 50 l.
3. Proportions:
1 mol of gas at normal level – 22.4 liters;
X mol (CO2) – 50 liters. hence, X mol (CO2) = 1 * 50 / 22.4 = 2.23 mol;
X mol (C6H14) – 2.23 mol (CO2);
-2 mol                  -12 mol from here, X mol (C6H14) = 2 * 2.23 / 12 = 0.37 mol.
4. Find the mass of the original substance:
m (C6H14) = Y * M = 0.37 * 86 = 31.82 g.
Answer: to carry out the reaction, hexane with a mass of 31.82 g is required.