By 200g. a solution containing 60% salt was added 300 g of a solution containing 50% of the same

By 200g. a solution containing 60% salt was added 300 g of a solution containing 50% of the same salt. What percentage of salt is contained in the resulting solution.

Let’s find what the mass of the resulting solution is equal to.

From the condition of the problem it is known that the mass of the first solution was 200 g, and the mass of the other solution was 300 g, therefore, the mass of the resulting solution is 200 + 300 = 500 g.

Let’s find what is the mass of salt in the resulting solution.

According to the condition of the problem, the first solution contained 60% salt, and the second solution contained 50% salt, therefore, the mass of salt in the resulting solution is (60/100) * 200 + (50/100) * 300 = (6/10) * 200 + (1/2) * 300 = 120 + 150 = 270 g.

Therefore, the percentage of salt in the resulting solution is:

100 * 270/500 = 100 * 27/50 = 27 * 100/50 = 27 * 2 = 54%.

Answer: the percentage of salt in the resulting solution is 54%.