By calcining purified chalk weighing 220 kg, we obtained 117 kg of quicklime. Determine the yield of the reaction product.

1. Let’s write down the reaction equation:

CaCO3 = CaO + CO2;

2.Calculate the theoretical chemical amount of calcium carbonate:

n (CaCO3) = m (CaCO3): M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

ntheor (CaCO3) = 220: 100 = 2.2 kmol;

3. according to the reaction equation, we find the theoretical amount of calcium oxide:

ntheor (CaO) = ntheor (CaCO3) = 2.2 kmol;

4. calculate the practical chemical amount of quicklime:

npractic (CaO) = m (CaO): M (CaO);

M (CaO) = 40 + 16 = 56 g / mol;

npract (CaO) = 117: 56 = 2.09 kmol;

5.Let’s determine the product yield:

ν (CaO) = npract (CaO): ntheor (CaO) = 2.09: 2.2 = 0.95 or 95%.

Answer: 95%.