By decomposing 200 g of limestone (calcium carbonate), 100 g of calcium oxide was obtained.

By decomposing 200 g of limestone (calcium carbonate), 100 g of calcium oxide was obtained. Determine the mass fraction of the reaction yield.

CaCO3 = CaO + CO2
n (CaCO3) = m \ M = 200 \ 100 = 2 mol
n (CaO) = n (CaCO3) = 2 mol according to the reaction equation
m (CaO) = nM = 2 * 56 = 112 g
output = m (practical) \ m (theory) = 100 \ 112 = 89.3%



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