By fusing 60 kg of limestone with sand, 58 kg of calcium silicate were obtained.

By fusing 60 kg of limestone with sand, 58 kg of calcium silicate were obtained. Mass fraction of calcium carbonate in this limestone.

1. We write down the reaction equation:

CaCO3 + SiO2 = CaSiO3 + CO2;

2.Calculate the chemical amount of the obtained calcium silicate:

n (CaSiO3) = m (CaSiO3): M (CaSiO3);

M (CaSiO3) = 40 + 28 + 3 * 16 = 116 g / mol;

n (CaSiO3) = 58000: 116 = 500 mol;

3.the chemical amounts of the initial carbonate and the resulting silicate are equal to each other according to the equation:

n (CaCO3) = n (CaSiO3) = 500 mol;

4. find the mass of carbonate:

m (CaCO3) = n (CaCO3) * M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

m (CaCO3) = 500 * 100 = 50,000 g = 50 kg;

5.Calculate the proportion of calcium carbonate in limestone:

w (CaCO3) = m (CaCO3): m (limestone);

w (CaCO3) = 50: 58 = 0.8621 or 86.21%.

Answer: 86.21%.