By mixing 120 g of a 24% sulfuric acid solution with 180 g of the second (other) sulfuric acid solution, a 33%

By mixing 120 g of a 24% sulfuric acid solution with 180 g of the second (other) sulfuric acid solution, a 33% sulfuric acid solution was obtained. Determine the percentage of acid contained in the second solution.

We find the total mass of the resulting mixture.

Let’s sum up the weight of each of the two acids.

180 + 120 = 300 grams.

Determine the weight of the acid in the resulting mixture.

To do this, multiply 300 grams by the percentage of acid content in it.

300 * 33% = 300 * 0.33 = 99 grams.

We find how many grams of acid were in the first solution.

120 * 24% = 120 * 0.24 = 28.8 g.

This means that the second solution contained:

99 – 28.8 = 70.2 g of acid.

From this it follows that the acid content in the second solution was equal to:

70.2 / 180 * 100% = 7020/180 = 39%.

Answer: 39%.