By nitration of benzene, 22.24 nitrobenzene was obtained. Find the mass of the reacted benzene.

Let’s execute the solution:

According to the condition of the problem, we will write the data:

C6H6 + HNO3 = C6H5NO2 + H2O – substitutions, nitrobenzene is released;

Calculations:
M (C6H6) = 78 g / mol;

M (C6H5NO2) = 123 g / mol.

We find the amount of the product, if the mass is known:
Y (C6H5NO2) = m / M = 22.24 / 123 = 0.18 mol.

Y (C6H6) = 0.18 mol since the amount of substances is 1 mol.

Determine the mass of the original substance:
m (C6H6) = Y * M = 0.18 * 78 = 14.04 g

Answer: the mass of benzene is 14.04 g