By nitriding benzene, we obtained nitrobenzene weighing 105 g. What mass of acid was required for this reaction.

1. Let’s compose the equation of benzene nitration:

C6H6 + HNO3 = C6H5NO2 + H2O;

2. Let’s calculate the chemical amount of the obtained nitrobenzene:

n (C6H5NO2) = m (C6H5NO2): M (C6H5NO2);

M (C6H5NO2) = 6 * 12 + 5 + 14 + 2 * 16 = 123 g / mol;

n (C6H5NO2) = 105: 123 = 0.8537 mol;

3. Set the amount of nitric acid:

n (HNO3) = n (C6H5NO2) = 0.8537 mol;

4. Find the mass of the acid that went into the reaction:

m (HNO3) = n (HNO3) * M (HNO3);

M (HNO3) = 1 + 14 + 3 * 16 = 63 g / mol;

m (HNO3) = 0.8537 * 63 = 53.78 g.

Answer: 53.78 g.