By passing carbon monoxide (IV) through a calcium hydroxide solution, 81 g of calcium bicarbonate were obtained.

By passing carbon monoxide (IV) through a calcium hydroxide solution, 81 g of calcium bicarbonate were obtained. Determine the volume and amount of carbon monoxide (IV) substance that was passed through the solution.

Given:
m (Ca (HCO3) 2) = 81 g?
n (CO2) -?;
V (CO2) -?.
Solution.
Let’s write the reaction equation:
Ca (OH) 2 + 2CO2 = Ca (HCO3) 2.
To solve the problem, the following formulas will be used:
n = m / M;
V = n * VM.
We calculate M (Ca (HCO3) 2) = 40 + 2 * (1 + 12 + 3 * 16) = 162 (g / mol).
Find n (Ca (HCO3) 2) = 81/162 = 0.5 (mol).
It follows from the reaction equation that the amount of CO2 is 1 mol.
Let’s find the volume of CO2:
V (CO2) = 1 * 22.4 = 22.4 (L).
Answer: the amount of carbon dioxide is 1 mol, the volume of carbon dioxide is 22.4 liters.

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