# By passing carbon monoxide (IV) through a calcium hydroxide solution, 81 g of calcium bicarbonate were obtained.

**By passing carbon monoxide (IV) through a calcium hydroxide solution, 81 g of calcium bicarbonate were obtained. Determine the volume and amount of carbon monoxide (IV) substance that was passed through the solution.**

Given:

m (Ca (HCO3) 2) = 81 g?

n (CO2) -?;

V (CO2) -?.

Solution.

Let’s write the reaction equation:

Ca (OH) 2 + 2CO2 = Ca (HCO3) 2.

To solve the problem, the following formulas will be used:

n = m / M;

V = n * VM.

We calculate M (Ca (HCO3) 2) = 40 + 2 * (1 + 12 + 3 * 16) = 162 (g / mol).

Find n (Ca (HCO3) 2) = 81/162 = 0.5 (mol).

It follows from the reaction equation that the amount of CO2 is 1 mol.

Let’s find the volume of CO2:

V (CO2) = 1 * 22.4 = 22.4 (L).

Answer: the amount of carbon dioxide is 1 mol, the volume of carbon dioxide is 22.4 liters.