By reacting carbon monoxide (IV) with calcium hydroxide, 40 g of calcium carbonate were obtained.

By reacting carbon monoxide (IV) with calcium hydroxide, 40 g of calcium carbonate were obtained. Calculate the volume and mass of carbon monoxide (IV) reacted.

1. Let’s compose the reaction equation:

Ca (OH) 2 + CO2 = CaCO3 + H2O.

2. Find the amount of calcium carbonate:

n (CaCO3) = m (CaCO3) / M (CaCO3) = 40 g / 100 g / mol = 0.4 mol.

3. Using the equation, we compose the ratio of the amounts of calcium carbonate and carbon dioxide:

n (CaCO3) = n (CO2) = 0.4 mol.

4. Find the mass and volume of carbon dioxide (Vm is a constant equal to 22.4 mol / l):

m (CO2) = n (CO2) * M (CO2) = 0.4 mol * 44 g / mol = 17.6 g.

V (CO2) = n (CO2) * Vm (CO2) = 0.4 mol * 22.4 mol / L = 8.96 L.

Answer: m (CO2) = 17.6 g; V (CO2) = 8.96 l.