By reduction of 123 g of nitrobenzene, 88 g of aniline was obtained. Calculate the product yield

By reduction of 123 g of nitrobenzene, 88 g of aniline was obtained. Calculate the product yield as a percentage of the theoretically possible

1. Let us write down the equation of nitrobenzene reduction:
C6H5NO2 + 3H2 → C6H5NH2 + 2H2O;
2.Calculate the theoretical chemical amount of nitrobenzene:
ntheor (C6H5NO2) = m (C6H5NO2): M (C6H5NO2);
M (C6H5NO2) = 6 * 12 + 5 + 14 + 2 * 16 = 123 g / mol;
ntheor (C6H5NO2) = 123: 123 = 1 mol;
3. Determine the theoretical amount and mass of aniline:
ntheor (C6H5NH2) = ntheor (C6H5NO2) = 1 mol;
mtheor (C6H5NH2) = ntheor (C6H5NH2) * M (C6H5NH2);
M (C6H5NH2) = 6 * 12 + 5 + 14 + 2 = 92 g / mol;
mtheor (C6H5NH2) = 1 * 93 = 93 g;
4. calculate the product yield:
ν (C6H5NH2) = mpract (C6H5NH2): mtheor (C6H5NH2) = 88: 93 = 0.9462 or 94.62%.
Answer: 94.62%.



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