By what percentage will the area of a rectangle with measurements of 30 cm and 20 cm

By what percentage will the area of a rectangle with measurements of 30 cm and 20 cm change if the larger side is increased by 10%, and the other is reduced by 10%?

According to the condition of the problem, the large side of this rectangle is 30 cm, and the smaller side is 20 cm.

Then the area of ​​this rectangle is 30 * 20 = 600 cm ^ 2.

If the larger side of this rectangle is increased by 10%, and the smaller one is reduced by 10%, then the sides of the resulting rectangle will be 30 + (10/100) * 30 = 30 + 0.1 * 30 = 30 + 3 = 33 cm and 20 – (10 / 100) * 20 = 20 – 0.1 * 20 = 20 – 2 = 18 cm, and the area of ​​the resulting rectangle will be 33 * 18 = 594 cm ^ 2.

Therefore, the area of ​​the original rectangle will decrease by 600 – 594 = 6 cm ^ 2, which in percentage terms will be 100 * 6/600 = 100/100 = 1%.

Answer: the area of ​​the rectangle will decrease by 1%; the length and width of the rectangle are redundant data in the problem statement



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