By what percentage will the area of a rectangle with measurements of 30 cm and 20 cm
By what percentage will the area of a rectangle with measurements of 30 cm and 20 cm change if the larger side is increased by 10%, and the other is reduced by 10%?
According to the condition of the problem, the large side of this rectangle is 30 cm, and the smaller side is 20 cm.
Then the area of this rectangle is 30 * 20 = 600 cm ^ 2.
If the larger side of this rectangle is increased by 10%, and the smaller one is reduced by 10%, then the sides of the resulting rectangle will be 30 + (10/100) * 30 = 30 + 0.1 * 30 = 30 + 3 = 33 cm and 20 – (10 / 100) * 20 = 20 – 0.1 * 20 = 20 – 2 = 18 cm, and the area of the resulting rectangle will be 33 * 18 = 594 cm ^ 2.
Therefore, the area of the original rectangle will decrease by 600 – 594 = 6 cm ^ 2, which in percentage terms will be 100 * 6/600 = 100/100 = 1%.
Answer: the area of the rectangle will decrease by 1%; the length and width of the rectangle are redundant data in the problem statement