Calcium hydroxide weighing 148 g reacted with hydrochloric acid. How much hydrochloric acid has been consumed?

We implement the solution:
1. Let us write the equation according to the problem statement:
m = 148 g. X g. -?
Ca (OH) 2 + 2HCl = CaCl2 + 2H2O – ion exchange reaction, obtained calcium chloride, water;
2. Calculation by formulas:
M Ca (OH) 2 = 74 g / mol;
M (HCl) = 36.5 g / mol.
3. Determine the number of moles of the starting material, if the mass is known:
Y Ca (OH) 2 = m / M = 148/74 = 2 mol.
4. Proportion:
2 mol Ca (OH) 2 – X mol (HCl);
-1 mol -2 mol hence, X mol (HCl) = 2 * 2/1 = 4 mol.
5. Find the mass of acid:
m (HCl) = Y * M = 4 * 36.5 = 146 g.
Answer: to carry out the reaction, hydrochloric acid weighing 146 g is required.