Calcium oxide weighing 70 kg was obtained from limestone. Calculate the amount of calcium oxide substance CaO.

Calcium oxide weighing 70 kg was obtained from limestone. Calculate the amount of calcium oxide substance CaO. What mass of slaked lime can be obtained from a given amount of calcium oxide?

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

When decomposing 1 mol of limestone, 1 mol of calcium oxide and 1 mol of carbon monoxide is obtained.

Let’s calculate the chemical amount of calcium oxide. To do this, divide its weight by its molar mass.

M CaO = 40 + 16 = 56 grams / mol; N CaO = 70,000/56 = 1,250 mol;

Let us calculate the weight of 1 250 mol of slaked lime.

For this purpose, we multiply the amount of the substance by its molar weight.

M Ca (OH) 2 = 40 + (16 + 1) x 2 = 74 grams / mol;

m Ca (OH) 2 = 1 250 x 74 = 92 500 grams = 92.5 kg;



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