Calculate and indicate the volume of gas that can be formed when a sufficient amount

Calculate and indicate the volume of gas that can be formed when a sufficient amount of aluminum is added to a solution containing 98.6 g of sulphate acid.

Let’s find the amount of substance Н2SO4.

M (H2SO4) = 98 g / mol.

n = 98.6 g: 98 g / mol = 1 mol.

Let’s compose the reaction equation, find in what quantitative ratios the substances are.

2Al + 3 Н2SO4 = Al2 (SO4) 3 + 3H2 ↑.

For 3 mol of Н2SO4, there are 3 mol of H2.

The substances are in quantitative ratios of 1: 1.

The amount of substance is equal.

n (H2) = n (H2SO4) = 1 mol.

Let’s find the volume of H2.

V = n Vn, where Vn is the molar volume of the gas equal to 22.4 l / mol.

V = 1 mol × 22.4 L / mol = 22.4 L.

Answer: 22.4 liters.