Calculate how many grams of 10% solutions of the starting salts will be required to obtain 75 g of calcium carbonate.

univerkov | April 11, 2021 | education

Decision:
1) CaCl₂ + Na2C0₃ = CaCO₃ + 2NaCl

2) n (CaCO₃) = 75/100 = 0.75 mol

3) n (CaCl₂) = n (Na₂CO₃) = n (CaCO₃) = 0.75 mol

4) n (CaCl₂) = 0.75 * 111 = 83.25 g

5) m (Na₂CO₃) = 0.75 * 106 = 79.5 g

6) m (p-pa CaCl₂) = 83.25 * 100/10 = 832.5 g

7) m (Na₂CO₃) = 79.2 * 100/10 = 792 g

Answer: 832.5 g, 792 g

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