Calculate how many grams of magnesium chloride is formed when 2.4 magnesium reacts with dilute hydrochloric acid.

Let’s write the reaction equation:

Mg + 2HCl = MgCl2 + H2 ↑

The amount of magnesium substance:

v (Mg) = m (Mg) / M (Mg) = 2.4 / 24 = 0.1 (mol).

According to the reaction equation, 1 mole of MgCl2 is formed per 1 mole of Mg, therefore:

v (MgCl2) = v (Mg) = 0.1 (mol).

Thus, the mass of the resulting magnesium chloride:

m (MgCl2) = v (MgCl2) * M (MgCl2) = 0.1 * 95 = 9.5 (g).

Answer: 9.5 g.