# Calculate how many grams of potassium sulfate will be released when 4.9 grams of sulfuric acid

September 24, 2021 | education

| **Calculate how many grams of potassium sulfate will be released when 4.9 grams of sulfuric acid reacts with potassium hydroxide.**

H2SO4 + 2KOH = K2SO4 + 2H2O

According to the periodic table, we determine the molar mass of sulfuric acid: M = 1 * 2 + 32 + 16 * 4 = 98 g / mol. And the molar mass of potassium sulfate: M = 39 * 2 + 32 + 16 * 4 = 174 g / mol.

Let’s find the amount of sulfuric acid: n = m / M = 4.9 g / 98 g / mol = 0.05 mol.

According to the reaction, 1 mol of potassium sulfate is formed from 1 mol of sulfuric acid, which means n (H2SO4) = n (K2SO4) = 0.05 mol.

Find the mass of potassium sulfate: m = n * M = 0.05 mol * 174 g / mol = 8.7 mol.

Answer: m (K2SO4) = 8.7 mol.

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