Calculate how many grams of potassium sulfate will be released when 4.9 grams of sulfuric acid
September 24, 2021 | education
| Calculate how many grams of potassium sulfate will be released when 4.9 grams of sulfuric acid reacts with potassium hydroxide.
H2SO4 + 2KOH = K2SO4 + 2H2O
According to the periodic table, we determine the molar mass of sulfuric acid: M = 1 * 2 + 32 + 16 * 4 = 98 g / mol. And the molar mass of potassium sulfate: M = 39 * 2 + 32 + 16 * 4 = 174 g / mol.
Let’s find the amount of sulfuric acid: n = m / M = 4.9 g / 98 g / mol = 0.05 mol.
According to the reaction, 1 mol of potassium sulfate is formed from 1 mol of sulfuric acid, which means n (H2SO4) = n (K2SO4) = 0.05 mol.
Find the mass of potassium sulfate: m = n * M = 0.05 mol * 174 g / mol = 8.7 mol.
Answer: m (K2SO4) = 8.7 mol.
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