Calculate how many grams of Trilon B will be required to prepare 250 ml of a 0.05 M solution.

Let’s find the required amount of substance to prepare this solution.

To do this, multiply the volume of the solution and its molar concentration.

In order to prepare such a solution, it is necessary to weigh and dissolve in water 0.25 x 0.05 = 0.013 mol of Trilon B.

Let’s find the required mass of Trilon B.

To do this, multiply the molar weight of the salt by the chemical amount of the substance.

M trilon B = 336 grams / mol;

m Trilon B = 0.013 x 336 = 4.368 grams;