Calculate how many volumes of chlorine can be obtained by reacting 43.5 g of manganese

Calculate how many volumes of chlorine can be obtained by reacting 43.5 g of manganese oxide with concentrated hydrochloric acid.

Let’s compose the equation of the process:
MnO2 + 4HCl (conc.) = MnCl2 + Cl2 + 2H2O – OBP, chlorine is evolved;

Calculations by formulas:
M (MnO2) = 86.9 g / mol;

M (Cl2) = 71 g / mol.

Determine the amount of the original substance:
Y (MnO2) = m / M = 43.5 / 86.9 = 0.5 mol;

Y (Cl2) = 0.5 mol since the amount of substances is 1 mol.

Find the volume of the product:
V (Cl2) = 0.5 * 22.4 = 11.2 L

Answer: Chlorine was obtained with a volume of 11.2 liters.



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