Calculate how much ammonia was taken to obtain 20.6 ammonium acetate from acetic acid, the yield of which was 70%

Let’s calculate the chemical ammonium acetate.

M NH4CH3COO = 14 + 4 + 12 + 3 + 12 + 16 x 2 = 77 grams / mol;

N NH4CH3COO = 20.6 / 77 = 0.2675 mol;

Taking into account the reaction yield of 70%, it is necessary to take 0.2675 / 0.7 = 0.382 mol of ammonia.

Let’s find its volume. To do this, multiply the amount of substance by the volume of one mole of gas, which is 22.4 liters.

V NH3 = 0.382 x 22.4 = 561 liters;