Calculate how much carbon dioxide will be released when nitric acid interacts with 7 grams

Calculate how much carbon dioxide will be released when nitric acid interacts with 7 grams of calcium carbonate containing 11% non-carbonate impurities.

The reaction of dissolving calcium carbonate in nitric acid is described by the following chemical reaction equation:

CaCO3 + 2HNO3 = Ca (NO3) 2 + CO2 + H2O;

When 1 mol of calcium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of nitric acid.

Let’s calculate the chemical amount of a substance contained in 7 grams of sodium carbonate containing 11% impurities.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 7 x 0.89 / 100 = 0.062 mol;

Thus, when 0.062 mol of calcium carbonate is dissolved, 0.062 mol of carbon dioxide is synthesized.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.062 x 22.4 = 1.389 liters;