Calculate how much carbon monoxide (IV) CO2 will be released when nitric acid treatment

Calculate how much carbon monoxide (IV) CO2 will be released when nitric acid treatment of limestone (CaCO3) weighing 200 g, containing 20% impurities?

The reaction of interaction of limestone with nitric acid is described by the following chemical reaction equation:

CaCO3 + 2HNO3 = Ca (NO3) 2 + H2O + CO2;

When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 200 x 0.8 / 100 = 1.6 mol;

During the reaction, the same amount of carbon dioxide will be synthesized.

Let’s calculate its volume.

To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 1.6 x 22.4 = 35.84 liters;