Calculate how much carbon monoxide (IV) will be released when fusing calcium
| February 8, 2021 | education
Calculate how much carbon monoxide (IV) will be released when fusing calcium carbonate with 100 g of silica; containing 10% impurities.
Decision:
CaCO3 + SiO2 = CaSiO3 + CO2
100% -10% -90% = 0.9-pure silica
m (SiO2) = 0.9 x 100g = 90g is the mass of pure silica
M (SiO2) = 28 + 32 = 60g / mol
v (SiO2) = m / M = 90/60 = 1.5 mol
by reaction:
v (CО2) = v (SiО2) = 1.5 mol
V (CO2) = v (CO2) xVm = l .5 x 22.4 = 33.6 l
Answer: 33.6 l
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