Calculate how much chlorine in liters and grams it will take to get 202 g of chlorine methane.

Let us write the equation of the process of obtaining methane chloride:
CH4 + Cl2 = CH3Cl + HCl – substitution occurs in the light, chloromethane is released;

We make calculations:
M (Cl2) = 71 g / mol;

M (CH3Cl) = 50.5 g / mol.

Let’s determine the amount of the product:
Y (CH3Cl) = m / M = 202 / 50.5 = 4 mol;

Y (Cl2) = 4 mol since the amount of substances is 1 mol.

Determine the volume of the original substance:
V (Cl2) = 4 * 22.4 = 86.6 L

Answer: chlorine will require 86.6 liters of chlorine.