Let us write the equation of the process of obtaining methane chloride:
CH4 + Cl2 = CH3Cl + HCl – substitution occurs in the light, chloromethane is released;
We make calculations:
M (Cl2) = 71 g / mol;
M (CH3Cl) = 50.5 g / mol.
Let’s determine the amount of the product:
Y (CH3Cl) = m / M = 202 / 50.5 = 4 mol;
Y (Cl2) = 4 mol since the amount of substances is 1 mol.
Determine the volume of the original substance:
V (Cl2) = 4 * 22.4 = 86.6 L
Answer: chlorine will require 86.6 liters of chlorine.
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