Calculate how much chlorine in liters it will take to get 202 g of chlorine-methane.

CH4 + Cl2 = CH3Cl + HCl
n (CH3Cl) = 202 / (12 + 3 + 35.5) = 4 mol
n (cl2) = n (ch3cl) = 4
v (Cl2) = 4 * 22.4 = 89.6 liters



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