Calculate how much chlorine will be required to completely displace iodine from a 15 g solution

Calculate how much chlorine will be required to completely displace iodine from a 15 g solution containing sodium iodide.

In accordance with the condition of the problem, we write down the reaction equation:
2NaL + Cl2 = J2 + 2NaCl – redox reaction, iodine and sodium chloride are released;
Let’s calculate the molecular weights of substances:
M (NaJ) = 22.9 + 126.9 = 149.8 g / mol;
M (Cl2) = 35.5 * 2 = 71 g / mol;
Let’s calculate the number of moles of sodium iodide, if the mass is known:
Y (NaJ) = m / M = 15 / 149.8 = 0.1 mol;
Let’s make the proportion:
0.1 mol (NaJ) – X mol (Cl2);
-2 mol -1 mol hence, X mol (Cl2) = 0.1 * 1/2 = 0.05 mol;
Find the volume of chlorine by applying Avogadro’s law:
V (Cl2) = 0.05 * 22.4 = 1.12 L.
Answer: it took 1.12 liters to carry out the reaction. chlorine.