Calculate how much glucose can be obtained from 81 kg of starch if the glucose yield is 75%

Calculate how much glucose can be obtained from 81 kg of starch if the glucose yield is 75% of the theoretically possible?

1. (C6H10O5) n + n (H2O) = nC6H12O6
n (starch) = 81 \ 162 = 0.5 kmol = n theory (glucose)
2.n practical (glucose) = 0.75 * 0.5 = 0.375 kmol
m (glucose) = 0.375 * 180 = 67.5 kg



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