Calculate how much hydrogen can be obtained by dissolving 1 kg of aluminum in an excess of acid?

Given:
m (Al) = 1 kg = 1000 g

To find:
V (H2) -?

Decision:
1) Write the equation of a chemical reaction:
2Al + 6HCl => 2AlCl3 + 3H2 ↑;
2) Calculate the amount of substance Al:
n (Al) = m (Al) / M (Al) = 1000/27 = 37.04 mol;
3) Determine the amount of substance H2 (taking into account the coefficients in the reaction equation):
n (H2) = n (Al) * 3/2 = 37.04 * 3/2 = 55.56 mol;
4) Calculate the volume H2:
V (H2) = n (H2) * Vm = 55.56 * 22.4 = 1244.5 liters.

Answer: The volume of H2 is 1244.5 liters.