Calculate how much hydrogen is formed when 130 g of zinc reacts with sulfuric acid.

Zinc reacts violently with sulfuric acid to release hydrogen gas. In this case, zinc sulfate (zinc sulfate) is synthesized. This reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

The metal reacts with acid in equivalent molar amounts. At the same time, the same amounts of zinc sulfate and hydrogen are synthesized.

Let’s calculate the available chemical amount of zinc. To do this, divide the weight of pure metal by the weight of 1 mole of metallic zinc.

M Zn = 65 grams / mol; N Zn = 130/65 = 2 mol;

The same amount of hydrogen and zinc sulfate (zinc sulfate) will be synthesized. Let’s calculate the volume of this amount of hydrogen gas. To do this, multiply the amount of substance by the volume of 1 mole of ideal gas (22.4 liters).

N H2 = 2 mol; V H2 = 2 x 22.4 = 44.8 liters;



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