Calculate how much hydrogen reacts with 8 g of copper oxide.
Copper oxide is reduced with hydrogen gas. During the reaction, metallic copper and water are synthesized. This reaction is described by the following equation:
CuO + H2 = Cu + H2O;
Cupric oxide reacts with hydrogen in equal molar amounts. In this case, equal (equivalent) amounts of metallic copper and water are synthesized.
Let’s calculate the chemical amount of copper.
To do this, divide the weight of copper oxide by the weight of 1 mole of copper oxide.
M CuO = 64 + 16 = 80 grams / mol;
N Cu = 8/80 = 0.1 mol;
Thus, it is possible to carry out the reduction of 0.1 mol of copper oxide and obtain 0.1 mol of copper.
Let’s calculate the mass and volume of 0.1 mol of hydrogen.
M H2 = 2 grams / mol;
m H2 = 2 x 0.1 = 0.2 grams;
V H2 = 0.2 x 22.4 = 4.48 liters;