Calculate how much hydrogen sulfide is needed to neutralize 18 mol of lithium hydroxide?

univerkov | January 17, 2021 | education

Given:
m (LiOH) = 18 mol
To find:
n (H2S)
2LiOH + H2S = Li2S + 2H2O
n (LiOH): n (H2S) = 2: 1
n (H2S) = 18 mol / 2 = 9 mol
Answer: the amount of the substance of hydrogen sulfide acid is 9 mol

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