Calculate how much hydrogen will be released when sodium interacts
Calculate how much hydrogen will be released when sodium interacts with a solution of ethyl alcohol weighing 300 grams containing 80% ethanol.
When sodium metal interacts with ethyl alcohol (ethanol), sodium ethylate is synthesized and hydrogen gas is released. The reaction is described by the following equation:
C2H5OH + Na = C2H5ONa + ½ H2;
1 mole of alcohol reacts with 1 mole of metal. This synthesizes 1 mol of ethylate and 0.5 mol of gaseous hydrogen.
The amount of alcohol substance is.
M C2H5OH = 12 x 2 + 6 + 16 = 46 grams / mol;
N C2H5OH = 300 x 0.8 / 46 = 5.217 mol;
During this reaction, 5.217 / 2 = 2.609 mol of hydrogen will be released.
Let’s calculate its volume. To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).
V H2 = 2.609 x 22.4 = 58.44 liters;