Calculate how much of the aluminum substance was dissolved in hydrochloric acid, if 33.6 liters of hydrogen were released.

Calculate how much of the aluminum substance was dissolved in hydrochloric acid, if 33.6 liters of hydrogen were released. The second product of the reaction is aluminum chloride.

Aluminum reacts violently with hydrochloric acid. At the same time, the salt of aluminum chloride is synthesized and bubbles of hydrogen gas are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s calculate the chemical amount of the evolved hydrogen gas.

For this purpose, we find the ratio of its volume to the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

N H2 = 33.6 / 22.4 = 1.5 mol;

To obtain such an amount of hydrogen, it is necessary to dissolve 1.5 x 2/3 = 1 mole of aluminum.

Let’s calculate its weight.

M Al = 27 grams / mol;

m Al = 27 x 1 = 27 grams;