Calculate how much of the aluminum substance was dissolved in hydrochloric acid if 33.6

Calculate how much of the aluminum substance was dissolved in hydrochloric acid if 33.6 liters of hydrogen were released. The second product of the reaction is aluminum chloride.

Given:
V (H2) = 33.6 L

Find:
n (Al) -?

1) 2Al + 6HCl => 2AlCl3 + 3H2;
2) n (H2) = V / Vm = 33.6 / 22.4 = 1.5 mol;
3) n (Al) = n (H2) * 2/3 = 1.5 * 2/3 = 1 mol.

Answer: The amount of Al substance is 1 mol.