Calculate how much oxygen can be obtained by decomposing 43.4 g of mercury oxide.
| November 30, 2020 | education
2HgO = 2Hg + O2
find the amount of mole of oxygen
n (HgO) = 43.4 / 217 = 0.2 mol
according to the stoichiometric ratio, there is one mole of oxygen per 2 mole of oxide, then:
n (О2) = 0.2 / 2 = 0.1 mol
m (O2) = 32 * 0.1 = 3.2 g
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