Calculate how much oxygen should be used to burn 0.1 mol of aluminum?

Metallic aluminum reacts with oxygen to form alumina. The reaction is described by the following chemical reaction equation:

4Al + 3O2 = 2Al2O3;

N Al = 0.1 mol;

When burning aluminum for 1 mol of metal, it is necessary to take ¾ = 0.75 mol of oxygen. Let’s calculate its volume.

To do this, multiply the amount of oxygen by the volume of 1 mole of gas (filling volume 22.4 liters).

N O2 = 0.1 / 4 x 3 = 0.075 mol;

V O2 = 0.075 x 22.4 = 1.68 liters;