Calculate how much potassium is required for the reaction of 0.12 mol of sulfur.

univerkov | January 17, 2021 | education

Given:
n (S) = 0.12 mol
Find: m (K)
Decision:
2K + S = K2S
n (S): n (K) = 1: 2
n (K) = 0.12 mol * 2 = 0.24 mol
m (K) = n * M = 0.24 mol * 39 g / mol = 9.36 g
Answer: 9.36 g

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