Calculate how much sulfur dioxide can be obtained by burning 0.8 kg of sulfur if the product yield is 85%.

1. Let’s compose the equation of the chemical reaction:

S + O2 = SO2.

2. Find the chemical amount of sulfur:

0.8 kg = 800 g.

n (S) = m (S) / M (S) = 800 g / 32 g / mol = 25 mol.

3. According to the reaction equation, we find the theoretical chemical amount of sulfur dioxide, and at the end the volume (Vm is the molar volume, constant equal to 22.4 l / mol):

ntheor (SO2) = n (S) = 25 mol.

nprak (SO2) = ntheor (SO2) * η (SO2) / 100% = 25 mol * 85% / 100% = 21.25 mol.

V (SO2) = n (SO2) * Vm = 21.25 mol * 22.4 L / mol = 476 L.

Answer: V (SO2) = 476 liters.