Calculate how much sulfurous acid is needed to neutralize 4 mol of lithium hydroxide?

First, we write down the equation of reactions.
H2SO3 + 2 LiOH -> Li2SO3 + 2H2O.
Further, according to the reaction equation, we determine the amount of sulfurous acid.
X mol Н2SO3 – 4 mol LiOH
1 mol Н2SO3 – 2 mol LiOH
x mol = 1 mol × 4 mol ÷ 2 mol = 2 mol H2SO3
This means that in order to neutralize lithium hydroxide, 2 moles of sulfurous acid are required.
Answer: sulfurous acid will need 2 mol.



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