Calculate in what volumetric ratios the gases are in a mixture prepared from CO2

| May 13, 2021 | education

Calculate in what volumetric ratios the gases are in a mixture prepared from CO2 with a mass of 11 g, O2 with a mass of 24 g, N2 with a mass of 14 g.

1) Find the volume of carbon dioxide contained in 11 grams of the substance:

n (CO2) = m: M = 11 g: 44 g / mol = 0.25 mol

V (CO2) = n * Vm = 0.25 mol * 22.4 l / mol = 5.6 l.

2) Find the volume of oxygen contained in 24 grams of the substance:

n (O2) = m: M = 24 g: 32 g / mol = 0.75 mol

V (O2) = n * Vm = 0.75 mol * 22.4 l / mol = 16.8 l.

3) Find the volume of nitrogen contained in 14 grams of the substance:

n (N2) = m: M = 14 g: 14 g / mol = 1 mol

V (N2) = n * Vm = 1 mol * 22.4 l / mol = 22.4 l.

4) We got a volume ratio of 5.6: 16.8: 22.4,

we divide all parts by the smallest indicator 5.6 and we get a ratio of 1: 3: 6.

Answer: the gases in the mixture are in a volume ratio of 1: 3: 6.



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