Calculate the amount of alumina substance formed as a result of the interaction of aluminum with an amount of 4.5 mol

Calculate the amount of alumina substance formed as a result of the interaction of aluminum with an amount of 4.5 mol of substance with a sufficient amount of oxygen (4Al + 3O2 = 2Al2O3)

Given:
n (Al) = 4.5mol + O2
Find: n (Al2O3)
Decision:
4Al + 3O2-> 2Al2O3
Let’s make the proportion 4.5 / 4 = x / 2 x = 2.25 mol (Al2O3)
Answer: 2.25 mol



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