Calculate the amount of alumina substance that will react with 8 liters of hydrogen.

univerkov | March 8, 2021 | education

Given:
V (H2) = 8 l

To find:
n (Al2O3) -?

1) Al2O3 + 3H2 => 2Al + 3H2O;
2) n (H2) = V / Vm = 8 / 22.4 = 0.36 mol;
3) n (Al2O3) = n (H2) / 3 = 0.36 / 3 = 0.12 mol.

Answer: The amount of substance Al2O3 is 0.12 mol.

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