Calculate the amount of aluminum chloride substance obtained by dissolving aluminum weighing 108

Calculate the amount of aluminum chloride substance obtained by dissolving aluminum weighing 108 grams in hydrochloric acid.

Let’s write down the solution sequentially:
1. Let’s compose the reaction equation:
2Al + 6HCl = 2AlCl3 + 3H2 – redox reaction, hydrogen and aluminum chloride are released;
2. Let’s calculate the molar masses:
M (Al) = 26.9 g / mol;
M (AlCl3) = 26.9 + 35.5 * 3 = 133.4 g / mol;
3. Let us determine the number of moles of Al if its mass is known:
Y (Al) = m (Al) / M (Al); Y (Al) = 108 / 26.9 = 4 mol;
4. Let’s compose the proportion according to the reaction equation data:
4 mol (Al) – X mol (AlCl3)
-2 mol – 2 mol hence, X mol (AlCl3) = 4 * 2/2 = 4 mol;
Answer: The amount of aluminum chloride is 4 mol.