Calculate the amount of aluminum oxide substance, which is formed during combustion of aluminum

Calculate the amount of aluminum oxide substance, which is formed during combustion of aluminum in oxygen with the amount of substance 2.5 mol

Elemental aluminum reacts with oxygen gas to form alumina. The reaction is described by the following chemical reaction equation:

4Al + 3O2 = 2Al2O3;

Let’s calculate the chemical amount of aluminum. For this purpose, we divide the weight of the existing substance by its molar weight.

N Al = 2.5 mol;

When burning this amount of aluminum, 2 times less amount of aluminum oxide will be synthesized. Let’s find its mass.

To do this, multiply the amount of the synthesized substance by its molar weight.

M Al2O3 = 27 x 2 + 16 x 3 = 102 grams / mol;

N Al2O3 = 2.5 / 2 = 1.25 mol;

m Al2O3 = 1.25 x 102 = 127.5 grams;