Calculate the amount of ammonia substance if 21.4 g of ammonium chloride has entered

Calculate the amount of ammonia substance if 21.4 g of ammonium chloride has entered into a reaction with calcium hydroxide.

This reaction proceeds according to the following chemical reaction equation:

2NH4Cl + CaO = 2NH3 + CaCl2;

Let’s calculate the chemical amount of ammonium chloride. To do this, we divide its weight by its molar mass.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

The weight of ammonium chloride will be:

N NH4 Cl = 21.4 / 53.5 = 0.4 mol;

With 0.4 mol of ammonium chloride, 0.4 / 2 = 0.2 mol of calcium oxide will react. This will synthesize 0.4 mol of ammonia.

Let’s calculate its weight.

M NH3 = 14 + 3 = 17 grams / mol;

m NH3 = 0.4 x 17 = 6.8 grams;



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